The?atomic?radius?of an element is a measure of the size of an atom
It is the distance between the?nucleus?of an atom and the outermost electron shell
It can be quite hard to determine exactly where the boundary of an atom lies, so a variety of approches are taken such as half the mean distance between two adjacent atoms
This will vary depending on the type of structure and bonding, but it gives a comparative value for atoms
The atomic radius of an atom is the typical distance between the nucleus and the outermost electron shell
Atomic radii show predictable patterns across the periodic table
They generally?decrease?across each period
They generally?increase?down each group
These trends can be explained by the?electron?shell?theory
Atomic radii decrease as you move across a period as the atomic number increases (increased positive?nuclear?charge) but at the same time extra electrons are added to the same?principal?quantum?shell
The larger the nuclear charge, the greater the pull of the nuclei on the electrons which results in smaller atoms
Atomic radii increase moving down a group as there is an increased number of shells going down the group
The electrons in the?inner?shells?repel the electrons in the?outermost shells,?shielding?them from the positive nuclear charge
This weakens the pull of the nuclei on the electrons resulting in larger atoms
Trends in the atomic radii across a period and down a group
The diagram shows that the atomic radius increases sharply between the?noble?gas?at the end of each period and the?alkali?metal?at the beginning of the next period
This is because the?alkali metals?at the beginning of the next period have?one?extra principal quantum shell
This increases shielding of the outermost electrons and therefore increases the atomic radius
Ionic radius
The?ionic?radius?of an element is a measure of the size of an ion
Ionic radii show predictable patterns
The trend down a group is the same as atomic radius - it increases as the number of shells increases
The trend across a period is not so straightforward as it depends on whether it is positive or negative ions being considered
These trends can also be explained by the?electron?shell?theory
Ions with?negative?charges are formed by atoms?accepting?extra electrons while the?nuclear?charge?remains the same
The extra electrons experience repulsion with the other valence electrons which increases the ionic radius
The greater the negative charge, the larger the ionic radius
Positively?charged ions are formed by atoms?losing?electrons
The?nuclear charge?remains the same but there are now fewer electrons which undergo a?greater electrostatic force of attraction?towards the nucleus which decreases the ionic radius
The greater the positive charge, the smaller the ionic radius
Trends in the ionic radii across a period and down a group
Worked Example
Which option shows atoms in order of decreasing atomic radius?
A. N > C > Be > Mg
B. Mg > N > C > Be
C. Be > C > N > Mg
D. Mg > Be > C > N
Answer:
Option?D?is the correct answer
First, you need to identify that Be, C and N are all in period 2, but Mg is in period 3, so Mg will have the biggest radius.
Secondly, atomic radius decreases across the period so Be, C and N decrease in that order as they belong to groups 2, 14 and 15, respectively