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IB DP Physics: HL復(fù)習(xí)筆記5.4.4 Solving Problems Involving Magnetic Forces

Category: IB課程, 教材筆記, 福利干貨 Date: 2022年8月1日 下午12:42

Solving Problems Involving Magnetic Forces

  • There is a lot of mathematics surrounding magnetism and magnetic forces
  • The key equations are:
Force on a current-carrying conductor:
F = BIL

Force on a moving charge:
F = Bqv

Radius of a moving charge in a magnetic field:
  • Below are two worked examples demonstrating different situations involving magnetic forces

Worked Example

A 5 cm length of wire is at 90° to the direction of an external magnetic field. When a current of 1.5 A flows through the wire it experiences a force of 0.06 N from the motor effect.

Calculate the magnetic flux density of the magnet.

Step 1: List the known quantities
  • Length,?L?= 5 cm = 0.05 m
  • Current,?I?= 1.5 A
  • Force,?F?= 0.06 N
Step 2: Write out the equation for magnetic force
F = BIL
Step 3: Rearrange the equation to make B the subject

Worked Example

This question is about the movement of an electrically charged particle into a magnetic field. An electron enters a magnetic field and moves in an approximately circular path as shown below.

5-4-4-electron-movement-we2_sl-physics-rn

  1. Explain whether the speed of the proton is the same when entering and exiting the magnetic field.
  2. The magnetic field has a strength of 0.3 T and the velocity of the electron before entering the magnetic field is 8.6 × 106?m s?1?to the left. Show that the radius of the motion of the electrons is 1.63 cm.
Part (a)
    • The answer is that the work done by the magnetic force on the charge must be zero
    • This is because the force itself is at right angles to the velocity
    • Since the work done is zero, therefore the kinetic energy does not change between entering and leaving the magnetic field
    • Therefore the speed is the same
Part (b)
Step 1: List the known quantities
  • Magnetic field strength,?B?= 0.3 T
  • Velocity of electron (before entering field),?v?= 8.6 × 106?m s?1?to the left
  • Radius of motion to be shown,?r?= 1.63 cm
Step 2: Equate the magnetic force and the force of circular motion
  • This can be done for the situation since the circular motion is caused by the magnetic force
Step 5: State final answer
R = 1.63 × 10?2?m =?1.63 cm?in a circular motion
轉(zhuǎn)載自savemyexams

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