Since most planets and satellites have a near circular orbit, the gravitational force?FG?between the sun or another planet provides the?centripetal force?needed to stay in an orbit
Both the gravitational force and centripetal force are?perpendicular?to the direction of travel of the planet
Consider a satellite with mass?m?orbiting Earth with mass?M?at a distance?r?from the centre travelling with linear speed?v
FG?=?Fcirc
Equating the gravitational force to the centripetal force for a planet or satellite in orbit gives:
Where:
v?= linear speed of the mass in orbit (m s-1)
G?=?Newton's Gravitational Constant
M?= mass of the object being orbited (kg)
r?= orbital radius (m)
This means that all satellites,?whatever their mass, will travel at the same speed?v?in a particular orbit radius?r
Since the direction of a planet orbiting in circular motion is constantly changing, the?centripetal acceleration acts towards the planet
A satellite in orbit around the Earth travels in circular motion
Time Period & Orbital Radius Relation
Since a planet or a satellite is travelling in circular motion when in order, its orbital time period?T?to travel the circumference of the orbit 2πr, the linear speed?v is:Graphical Representation of T2?∝ r3
The relationship between?T?and?r?can be shown using a logarithmic plot
T2?∝ r3
2 × log(T)?∝ 3 × log(r)
The graph of log(T) in years against log(r) in AU (astronomical units) for the planets in our solar system is a straight line graph:
The graph does not go through the origin since it has a negative y-intercept
Only the log of both?T?and?r?will produce a straight line graph
Worked Example
A binary star system constant of two stars orbiting about a fixed point?B. The star of mass?M1?has a circular orbit of radius?R1?and mass?M2?has a radius of?R2. Both have linear speed?v?and an angular speed ? about?B.
State the following formula, in terms of?G,?M2,?R1?and?R2
(i) The angular speed ? of?M1
(ii) The time period?T?for each star in terms of angular speed ?
Energy of an Orbiting Satellite
An orbiting satellite follows a circular path around a planet
Just like an object moving in circular motion, it has both kinetic energy (KE)?and?gravitational potential energy (GPE) and its?total?energy is always?constant
An orbiting satellite's total energy is calculated by:
A graph showing the kinetic, potential and total energy for a mass at varying orbital distances from a massive body
Total energy = Kinetic energy + Gravitational potential energy
This means that the satellite's KE and GPE are also both constant in a particular orbit
If the orbital radius of a satellite?decreases?its KE?increases?and its GPE?decreases
If the orbital radius of a satellite?increases?its KE?decreases?and its GPE?increases
At orbit Y, the satellite has greater GPE and less KE than at at orbit X
A satellite is placed in two orbits,?X and Y, around Earth
At orbit X, where the radius of orbit?r?is smaller, the satellite has a:
Larger gravitational force on it
Higher speed
Higher KE
Lower GPE
Shorter orbital?time period,?T
At orbit Y, where the radius of orbit?r?is larger, the satellite has a:
Smaller gravitational force on it
Smaller speed
Lower KE
Higher GPE
Longer orbital time period,?T
Worked Example
Two satellites A and B, of equal mass, orbit a planet at radii?R?and?3R?respectively. Which one of the following statements is incorrect?
A? ?A has more kinetic energy and less potential energy than B
B? ?A has a shorter time period and travels faster than?B
C? ?B has less kinetic energy and more potential energy than A
D? ?B has a longer time period and travels faster than A
ANSWER:? ? D
Since B is at a larger orbital radius (3R?instead of?R) it has a longer time period since?T2?∝ R3?for an orbiting satellite
However, satellite B will travel much slower than A
Its larger orbital radius means the force of gravity will be much lower for B than for A
Exam Tip
If you can't remember which way around the kinetic and potential energy increases and decreases, think about the velocity of a satellite at different orbits. When it is orbiting close to a planet, it experiences a larger gravitational pull and therefore orbits faster. Since the kinetic energy is proportional to v2, it, therefore, has higher kinetic energy closer to the planet. To keep the total energy constant, the potential energy must decrease too.
Orbital Energy Calculations
A synchronous orbit is:
When an orbiting body has a time period equal to that of the body being orbited and in the same direction of rotation as that body
These usually refer to?satellites?(the orbiting body) around?planets?(the body being orbited)
The orbit of a synchronous satellite can be above any point on the planet's surface and in any plane
When the plane of the orbit is directly above the equator, it is known as a?geosynchronous?orbit
Geostationary Orbit
Many communication satellites around Earth follow a?geostationary orbit
This is sometimes referred to as a?geosynchronous?orbit
This is a specific type of orbit in which the satellite:
Remains directly?above the equator
Is in the?plane of the equator
Always orbits at the?same point?above the Earth’s surface
Moves from?west to east?(same direction as the Earth spins)
Has an orbital time period equal to Earth’s rotational period of?24 hours
Geostationary satellites are used for?telecommunication?transmissions (e.g. radio) and television broadcast
A base station on Earth sends the TV signal up to the satellite where it is amplified and broadcast back to the ground to the desired locations
The satellite receiver dishes on the surface must point towards the same point in the sky
Since the geostationary orbits of the satellites are fixed, the receiver dishes can be fixed too
Low Orbits
Some satellites are in low orbits, which means their altitude is closer to the Earth's surface
One example of this is a?polar?orbit, where the satellite orbits around the north and south pole of the Earth
Low orbits are useful for taking high-quality photographs of the Earth's surface. This could be used for:
Weather
Military applications
Geostationary satellite in orbit
Worked Example
Calculate the distance above the Earth's surface that a geostationary satellite will orbit. Mass of the Earth = 6.0 × 1024?kg, Radius of the Earth = 6400?km
Orbital Motion
When a satellite is moving in orbital motion, the velocity of the satellite will be given by:
Where
ET?= The total energy of the satellite (J)
EP?= The potential energy of the satellite (J)
EK?= The kinetic energy of the satellite (J)
v?= the velocity of the satellite (m s-1)
M = mass of the Earth (or large body being orbited) (kg)
m = mass of satellite or orbiting object (kg)
G?= ?The gravitational constant?=?6.67 x 10-11?Nm2kg-2