Br2(l) + 2e-?? 2Br-(aq)? ? ? ? voltage = +1.09 V
Na+(aq) + e-?? Na(s)? ? ? ? voltage = -2.71 V
Br2(l) + 2e-?? 2Br-(aq)? ? ? ??E??= +1.09 V
2H+(aq) + 2e-?? H2(g)? ? ? ??E??= 0.00 V
Na+?(aq) + e-?? Na(s)? ? ? ??E??= -2.71 V
2H+?(aq) + 2e-?? H2(g)? ? ? ??E??= 0.00 V
Ecell??= (+1.09) - (-2.71)
= +3.80 V
Cu(s) → Cu2+(aq) + 2e-

Oxidation of copper ions
Cu2+(aq) + 2e-?→ Cu(s)

Reduction of copper ions
Cu2+?(aq) + 2e-?? Cu (s)
V2+?(aq) + 2e-?? V(s)
2H+?(aq) + 2e-?? H2?(g)

The standard electrode potential of a half-cell can be determined by connecting it to a standard hydrogen electrode
轉載自savemyexams
以上就是關于【CIE A Level Chemistry復習筆記5.3.3 Standard Electrode & Cell Potentials】的解答,如需了解學校/賽事/課程動態,可至翰林教育官網獲取更多信息。
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