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2015CAP Prize Exam加拿大高中物理大獎賽真題答案下載

Category: 國際競賽, 福利干貨, 競賽資料 Date: 2018年8月27日下午12:32

歷年CAP High School Prize Exam加拿大高中物理大獎賽

真題與答案下載

CAP Prize Exam加拿大物理奧林匹克學術活動

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2015 CAP Prize Exam完整版真題免費下載

共計3小時考試時間

此套試卷由25道選擇題以及3道大題組成

每道大題含有不同數量的小題

請點擊訪問下方鏈接進入下載頁面

2015 CAP Prize Exam完整版真題

2015CAP Prize Exam加拿大物理奧林匹克完整版答案免費下載

部分真題答案預覽：

Part A選擇題部分：

Part B簡答題部分

Solution to Problem 1：

From the red dashed red triangle on the picture one can measure the shooting angle to be θ = (22 ± 3?). Using the scale of the graph and attached to the exam “ruler” one can measure the maximum height above the end of the shooter h =( 9 ± 2) m and the horizontal distance from the end of the shooter to the place of maximum height L = (33 ± 2) m as well as the height H = 35m from the maximum to the drop point and total range? L’ = (83 ± 2) m

From the conservation of energy we have:

mgh + m(vcosθ)2/2 =? mv2/2

v = √2gh/(1-cosθ)2 = ?√2gh/sinθ2 = 35 ± 8 m/s

Horizontal speed is vh= v cosθ = 32 m/s and it should be constant without air resistance. Due to acceleration g it should take t1 =√2h/g = 1.3??? to reach height h and? t2 = √2H/g??? = 2.7 s to drop to the bottom.? During this time gravel should cover a distance of about 140 m. The observed range is much smaller (83 m) due to the air resistance.
The average horizontal speed is about

va = 83/4 = 21 m/s.

The final speed is:

va = (vh+vf)/2? vf = 2va? - vh? = 7 m/s

so the negative acceleration due to air resistance is

vf = vh – at??? a = (vh – vf)/t = 6m/s2

So the force acting on (for example) 1 kg of gravel was about 10 N. It is clear from the photograph that it strongly depend on the size of stones.

There were many ways to solve this problem and all the fully correct ones were awarded full marks and partly correct ones part marks.? ?

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